用C语言编写一段猜数字游戏,跟一般的不一样,规则如下
今天装修百科网给各位分享c语言猜数怎么设置的知识,其中也会对用C语言编写一段猜数字游戏,跟一般的不一样,规则如下(用c语言实现猜数字游戏)进行解释,如果能碰巧解决你现在面临的问题,别忘了关注本站,现在我们开始吧!
用C语言编写一段猜数字游戏,跟一般的不一样,规则如下
进行判断练习,若猜数是50,猜了40,范围变成40到100,若猜60,范围变成40到60.通过循环来控制。
#include
int main(void)
{
int a,low,k,he,d;
k=50; //k为答案数
low=1;
he=100;
scanf("%d",&a);
while(a!=k)
{
if(a<k)
{
low=a;

printf("猜数的范围是:%d到%d\n",low,he);
}
if(a>k)
{
he=a;
printf("猜数的范围是:%d到%d\n",low,he);
}
scanf("%d",&a);
}
printf("答案是:%d\n你猜对了,接受惩罚。",k);
return 0;
}
C语言编写猜数字游戏
#include
#include
//#include
unsigned char Num[4] = {0},getNum[4] = {0x20,0x20,0x20,0x20};
void help(void)
{
char i =0,j = 0;
for(i =0;i<4;i++)
{
for(j = 0;j<4;j++)
if(Num[j] == getNum[i])
{
if(i==j)
printf("%dth is correct!\r\n",i);
else
{
printf("%d is a correct data\r\n",getNum[i]);
}
}
else
{
if(i == 3&&j==3)
{printf("/********************small game*****************/\
input 4 data gess the random data,input h can get help\
");}
}
}
}
void main( void )
{
int orginal = 0,getdata = 0,i = 0,j = 0;
// { int a;a = 878*101;cout<<a<<endl}
//first = 0,second = 0,third = 0,fourth = 0;
/* Seed the random-number generator with GetTickCount so that
the numbers will be different every time we run.
*/
srand( (unsigned)time( NULL ) );
orginal = rand();
Num[3] = orginal%10000/1000;
Num[2] = orginal%1000/100;
Num[1] = orginal%1000%100/10;
Num[0] = orginal%10;
// printf(" %d",orginal);
for(i = 0;i<4;)
{
for(j = i+1;j<4;j++)
{
if(Num[i]==Num[j])
{ Num[i]++;if(Num[i]>9) Num[i] = 0;i=0;break;}
}
if(j == 4)i++;
}
get: for(i = 0;i<4;)
{
printf("input Num %d ",i);
scanf("%s",&getNum[i]);
if(getNum[i]-0x30>9||getNum[i]-0x30<0)
{
if (getNum[i] == 'H'||getNum[i] =='h')
{
help();
}
else
printf("input one num\r\n");
//if(i>0)i--;
}
else
{
getNum[i] -=0x30;
for(j = 0;j<i;j++)
{
if(getNum[i] == getNum[j])
{printf("have a same data,please input another\r\n"); break;}
}
if(j==i)
i++;
}
}
printf("you input num %d%d%d%d Y or N?\r\n",getNum[0],getNum[1],getNum[2],getNum[3]);
do{
scanf("%c",&j);
printf("%c",j);
if((j == 'N') || (j == 'n'))goto get;
}while( !((j == 'Y') || (j == 'y')));
printf("over");
}
求C语言程序,猜数游戏。
#include int main(){
int n,g,d,t;
n=156;
printf("请输入一个数字:\n");
scanf("%d",&g);
while(1)
{
if(gn)
{
d=g;
printf("太大了,\n再输入一个数字:");
scanf("%d",&t);
g=t;
}
if(g==n)
{
printf("你猜对了!就是156。\n");
break;
}
}
return 0;}
用C语言编写一个猜数字游戏的程序(要能运行的,求大神们帮忙啊)
#include#incude#include#include int main(){ srand(time(0)); //定义随机种子 int a= 0,b=0,c=1; a = rand()%101; printf("数字已经选好,开始猜吧:"); for(;;c++){ scanf("%d",&b); //输入猜的数 if(b> a) printf("wrong!!!大了\n"); else if (b<a) printf("wrong!!!小了\n"); if(b == a){ //如果猜的数字和随机数字相同, printf("right!!!真厉害,居然然你猜出来了!!\n"); if(c<= 3) printf("你只用了%d次就完成了,成绩优秀\n",c); else if(c <= 5) printf("你用了%d次完成,成绩及格\n",c); else printf("你用了%d次,很勉强\n",c); break; //游戏胜利,跳出循环 } } getch(); return 0;}
C语言编写猜数字游戏
#include
#include
//#include
unsigned char Num[4] = {0},getNum[4] = {0x20,0x20,0x20,0x20};
void help(void)
{
char i =0,j = 0;
for(i =0;i<4;i++)
{
for(j = 0;j<4;j++)
if(Num[j] == getNum[i])
{
if(i==j)
printf("%dth is correct!\r\n",i);
else
{
printf("%d is a correct data\r\n",getNum[i]);
}
}
else
{
if(i == 3&&j==3)
{printf("/********************small game*****************/\
input 4 data gess the random data,input h can get help\
");}
}
}
}
void main( void )
{
int orginal = 0,getdata = 0,i = 0,j = 0;
// { int a;a = 878*101;cout<<a<<endl}
//first = 0,second = 0,third = 0,fourth = 0;
/* Seed the random-number generator with GetTickCount so that
the numbers will be different every time we run.
*/
srand( (unsigned)time( NULL ) );
orginal = rand();
Num[3] = orginal%10000/1000;
Num[2] = orginal%1000/100;
Num[1] = orginal%1000%100/10;
Num[0] = orginal%10;
// printf(" %d",orginal);
for(i = 0;i<4;)
{
for(j = i+1;j<4;j++)
{
if(Num[i]==Num[j])
{ Num[i]++;if(Num[i]>9) Num[i] = 0;i=0;break;}
}
if(j == 4)i++;
}
get: for(i = 0;i<4;)
{
printf("input Num %d ",i);
scanf("%s",&getNum[i]);
if(getNum[i]-0x30>9||getNum[i]-0x30<0)
{
if (getNum[i] == 'H'||getNum[i] =='h')
{
help();
}
else
printf("input one num\r\n");
//if(i>0)i--;
}
else
{
getNum[i] -=0x30;
for(j = 0;j<i;j++)
{
if(getNum[i] == getNum[j])
{printf("have a same data,please input another\r\n"); break;}
}
if(j==i)
i++;
}
}
printf("you input num %d%d%d%d Y or N?\r\n",getNum[0],getNum[1],getNum[2],getNum[3]);
do{
scanf("%c",&j);
printf("%c",j);
if((j == 'N') || (j == 'n'))goto get;
}while( !((j == 'Y') || (j == 'y')));
printf("over");
}
设计一个简单的猜数游戏:先由计算机“想”一个数请用户猜,如果用户猜对了,则计算机给出提示信息“Rig
我给他做了一次"大手术",没问题吧?
#include
#include
#include
int main()
{
int x,magic,a=0,c=1;
char b;
do
{
srand(time(NULL)); //为函数rand()设置随机数种子
magic = rand() %100 +1; //magic为1~100间的一个数
printf("%d",magic);
printf("您每次游戏中,只有十次机会\n");
while(a<=10)
{
x = NULL;
scanf("%d",&x);
if(x>magic)
printf("Wrong,比magic大\n");
else if(x<magic)
printf("Wrong,比magic小\n");
else if(x==magic)
{
printf("Right\n");
a=a+1;
printf("你猜了%d次了\n",a);
break;
}
a++;
printf("你猜了%d次了\n",a);
}
a = 10;
if(a==10)
{
b = NULL;
a=0;
getchar();
printf("Do you want to continue?(回答Y/N或者y/n)\n");
scanf("%c",&b);
if(b=='y'||b=='Y')
c=1;
else if(b=='n'||b=='N')
c=0;
}
}while(c==1);
return 0;
}
编了一个C语言猜数游戏,想在后面加一个'是否继续游戏?'该如何操作
将你猜游戏的功能包成一个函数 比如说 fun
void fun()
{
猜字游戏处理
}
int main()
{
char ch;
do
{
fun();
printf("是否继续游戏? 是y");
ch=getchar();
}while( ch == 'y' );
return 0;
}